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88 lines
2.6 KiB
Python
88 lines
2.6 KiB
Python
2 years ago
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from sqlalchemy import create_engine
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from sqlalchemy.sql import select, update, insert
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from sqlalchemy.sql.expression import literal
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from .schema import metadata, articles
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from markdown import markdown
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import re
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import os
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import sys
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db_file = os.path.join(sys.argv[1], 'lazy_wiki.sqlite3')
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regex = re.compile(r'^\W+|^\W*\w+\W*')
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# instantiate an engine for connecting to a database
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engine = create_engine('sqlite:///{}'.format(db_file))
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# create tables if they don't exist
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metadata.create_all(engine)
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# connect to the database
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dbc = engine.connect()
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def select_longest_keyword_string_starts_with(string):
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'''
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Fetch the longest keyword that the given string starts with.
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'''
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query = select([articles]) \
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.where(literal(string).ilike(articles.c.title + '%'))
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# may be bottleneck
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results = [dict(u) for u in dbc.execute(query).fetchall()]
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if not results:
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return None
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return max(results, key = lambda keyword : len(keyword['title']))
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def select_article(keyword):
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'''
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Fetch an article associated with the given keyword.
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'''
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query = select([articles]) \
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.where(articles.c.title == literal(keyword))
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try:
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return dict(dbc.execute(query).fetchone())
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except:
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return None
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def select_formatted_article(keyword):
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'''
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Fetch an article associated with the given keyword,
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add hyperlinks to it, and format it to HTML.
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'''
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# get article content
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article = select_article(keyword)
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raw = article['content']
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# add hyperlinks to the content
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formatted = ''
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# until the raw content is empty
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while raw:
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# if the remaining raw content starts with a keyword
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word = select_longest_keyword_string_starts_with(raw)
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if word:
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# use original capitalization for hyperlink text
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original = raw[:len(word['title'])]
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# create a Markdown hyperlink
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word = '[{}](/view/{})'.format(original, word['title'])
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# cut off the start of the raw content
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raw = raw[len(original):]
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else:
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# cut a word off the start of the raw content
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word = regex.search(raw).group()
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raw = raw[len(word):]
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# add the hyperlink or word to the formatted content
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formatted += word
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article['content'] = markdown(formatted)
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return article
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def insert_article(**kwargs):
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query = insert(articles).values(**kwargs)
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dbc.execute(query)
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def update_article(title, **kwargs):
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query = update(articles) \
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.where(articles.c.title == literal(title)) \
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.values(**kwargs)
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dbc.execute(query)
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